Question

What will be the path of a charged particle projected along a magnetic field​

Answer 1

HELLO DEAR,

If the charge particle is projected along the magnetic field then , then by using equation

F= q( v× B)

F= qvBsinQ

F= qvBsin0°. ( Path of projection is along the magnetic field so Q=0°)

F=qv0

F= 0.

So, there is no force produce by magnetic field .Therefore no change in path of motion of charge particle.

I HOPE IT'S HELP YOU DEAR,

THANKS.

Answer 2

To find:

Path over charged particle projected along the magnetic field ?

Calculation:

The general expression of force experienced by a moving charge particle is given as :

$\therefore \: \vec{F} = q( \vec{v} \times \vec{B})$

$\boxed{ \bold{\implies \: | \vec{F} | = q \times v \times B \times \sin( \theta) }}$

• Here "F" is force , "q" is charge , "v" is velocity , "B" is magnetic field intensity and $\theta$ is the angle between velocity vector and field intensity vector.

When the charged particle is moving along the direction of magnetic field intensity , we can say that $\theta = {0}^{\circ}$.

Putting the available values:

$\implies \: | \vec{F}| = q \times v \times B \times \sin( {0}^{ \circ} )$

$\implies\: | \vec{F}| = 0 \: N$

So, the moving charged particle does not experience any force.

Hence, if we consider that the charge was initially moving linearly, then it will continue to move in that same direction without any deviation.