What will be the perimeter of rectangle if it's length of diagonal is 8√10
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Let the breadth be x cm, then , length = 3x cm . ∴diagonal =√(3x)2+x2cm=x√10cm. Thus ,x√10=8√10⇒=8. perimeter =2(3x+x)cm=8xcm=(8×8)cm=64cm.
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