Question

What will be the perimeter of rectangle whose area is 24 square and height is 6 cm?​

Answer 1

Answer:

A=wl

P=2(l+w)

Solving forP

P=2l+2A

l=2·6+2·24

6=20cm

Answer 2

$area \: \: of \: rectangle \\ = l \times b \\ 6 \: cm \: \times b \: = 24 \: {cm}^{2} \\ b = \frac{24 { \: cm}^{2} }{6 \: cm} \\ b \: = 4 \: cm$

$Perimeter \: of \: Rectangle \\ = 2( l+b)$

$= 2(6 \times 4)$

$= 2(24)$

$= 48 \: cm$