Question

What will be the perimeter of the rectangle given that area of ∆BOC is 4cm² and area of ∆COE is 1cm² and BE is perpendicular to AC.
Need complete solution which is short.​

Answer 1

LET ANGLE OBC = 30

AND ANGLE BOC = 90

THEN ANGLE OCB WILL BE 60.

THEREFORE 2OC = OB

( THERE IS RULE THAT THE LINE SEGMENT OPPOSITE 30° IS HALF OF THE OTHER )

OC = 2

OB = 4

THEN BC = 2√5( PYTHAGORAS THEOREM )

THEN AD WILL ALSO BE 2√5

LET ANGLE OAB = 30

ANGLE OBA = 60

AB = 4√5( PYTHAGORAS THEOREM )

CD = 4√5

PERIMETER OF ABCD

= AB + BC + CD + DA

( 4√5 ) + ( 2√5 ) + ( 4√5 ) + ( 2√5 )

FINAL ANSWER = 12√5

HOPE IT HELPS YOU

DON'T FORGET TO MAKE MY ANSWER AS BRILLIANTEST IF IT HELPS YOU