Question

What will be the period of oscillation if length of seconds pendulum is halved?

Answer 1

the equation for simple pendulum is T = 2pi*SQRT(L/g)

so if the pendulum length is halved then the length l should be change to half the length L/2 which gives you the solution finally to

T1=sqrt2*pi*sqrt(L/g) Let this be equal to T1

that results in time periodT1 to be 72% of the original time period (when length is L)

T1=0.72(T)

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