Question

What will be the ph of a solution formed by mixing 40 ml 0.1 molar hcl with 10 ml 0.45 mole nh?

Answer 1

Let molarity of hcl be M1 and vol be v1

M1v1 = 0.1×40 = 4

Let molarity of NaOH be M2 and vol be V2

M2v2 = 0.45×10= 4.5

Clearly m2v2 >m1v1

Therefore resulting solution will be basic.. So molarity if resultant solution ll be

M = m2v2 - m1v1/ v1 + v2 = 0.01

pOH = -log(0.01) = 2

Therefore, pH = 14 - pOH = 12.

Hope it helped! :)