Question

What will be the ph of a solution formed by mixing 40 ml of 0.10 m hcl with 10 ml of 0.45 m naoh?

Answer 1

0h- concentration in solution will be m1v1 -m2v2/v1+v2 = 10*0.45 - 40*0.1/50 = 0.01 therfore poh = -log(oh-)= 2

for ph we will use ph+poh= 14 therfore ph=12