what will be the ph of an aqueous solution of 1.0 m ammonium formate assuming completely dissociation (pka for formic acid = 3.8 and pka for ammonia
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Answered by
3
wallt of weak acid and weak base
ph=1/2pkw + 1/2pka -1/2pkb
=1/2×14 + 1/2×3.8 -1/2×4.8
=6.5
Answered by
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what will be the ph of an aqueous solution of 1.0 m ammonium formate assuming completely dissociation (pka for formic acid = 3.8 and pka for ammonia.
Your answer - wallt of weak acid and weak base
wallt of weak acid and weak baseph=1/2pkw + 1/2pka -1/2pkb
wallt of weak acid and weak baseph=1/2pkw + 1/2pka -1/2pkb=1/2×14 + 1/2×3.8 -1/2×4.8
wallt of weak acid and weak baseph=1/2pkw + 1/2pka -1/2pkb=1/2×14 + 1/2×3.8 -1/2×4.8=6.5
Hope it helps!!
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