What will be the ph value of 0.05 m ba(oh)2 solution?
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Its ph will be 13. SOLUTION: Ba(OH)2 - Ba2+ 2OH-
0.05 M X 2= 0.10M pOH= -log(0.10 M) = 1.00
pH = 14-pOH= 14 - 1.00=13
PLEASE MARK IT AS BRAINLIST
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