What will be the phenotype of the offspring if a cross is made between plants having round green (Rryy) seeds with the plant having wrinkled yellow (rrYy) seeds ?
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Explanation:
A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.
The dihybrid phenotypic ratio is 9:3:3:1.
So, the correct option is ‘9:3:3:1’.
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