Question

What will be the population after threem years when present population is `25,000 and population

increases at the rate of 3 % in first year, 4 % in second year and 5 % in third year?
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Answer 1

Answer:

This is a case of successive rates of increase

Step-by-step explanation:

Present population is 25000

After 3 years, the population becomes 25000 * [1 + (3/100)] * [1 + (4/100)] * [1 + (5/100)]

= 25000 * (103/100) * (104/100) * (105/100)

= 28119

So, the population after 3 years will be 28119

Answer 2

Present population = 25000

After 3 years, the population becomes

25000×$[1+\frac{3}{100} ]$×$[1+\frac{4}{100} ]$×$[1+\frac{5}{100} ]$

=25000×$(\frac{103}{100} )$×$(\frac{104}{100})$×$(\frac{105}{100} )$

= 28119

So, the population after 3 years will be 28119

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