What will be the position, nature and size of the image, if a 5 cm tall object is placed at a distance of 20 cm from a concave mirror of focal length 15 cm?
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1
Answer:
The image is virtual and height of the image is 15 cm. The image is formed at 60 cm on the back side of the mirror. Hence, The image is virtual and height of the image is 15 cm.
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ʀᴀᴅɪᴜs ᴏғ ᴄᴜʀᴠᴀᴛᴜʀᴇ (ʀ) = 30 ᴄᴍ
ғ = ʀ/2 = 30/2 = 15 ᴄᴍ
ᴜ = -20 ᴄᴍ,
ʜ= 5 ᴄᴍ.
1/ᴠ +1/ᴜ = 1/ғ
1/ᴠ = 1/ғ – 1/ᴜ
1/ᴠ = 1/15 – 1/-20
ᴠ = 8. 57 ᴄᴍ
ɪᴍᴀɢᴇ ɪs ᴠɪʀᴛᴜᴀʟ ᴀɴᴅ ᴇʀᴇᴄᴛ ᴀɴᴅ ғᴏʀᴍᴇᴅ ʙᴇʜɪɴᴅ ᴛʜᴇ ᴍɪʀʀᴏʀ.
ᴍ = -ᴠ/ᴜ
ᴍ = ʜɪ/ʜᴏ
ʜɪ/5= 8.57/20
= 0.428
ʜɪ = 0.428 x 5 = 2.14ᴄᴍ
ᴘᴏsɪᴛɪᴏɴ ᴏғ ɪᴍᴀɢᴇ: ʙᴇʜɪɴᴅ ᴛʜᴇ ᴍɪʀʀᴏʀ.
ɴᴀᴛᴜʀᴇ ᴏғ ɪᴍᴀɢᴇ: ᴠɪʀᴛᴜᴀʟ ᴀɴᴅ ᴇʀᴇᴄᴛ.
sɪᴢᴇ ᴏғ ᴛʜᴇ ɪᴍᴀɢᴇ: ᴅɪᴍɪɴɪsʜᴇᴅ.
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