what will be the position of an image if the object is placed 20cm in front of a convex mirror of focal length 15cm
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2
Object position (u) = - 20 cm (-ve sign due to position of object opposite to direction of incident ray)
Focal length (f) = -15 cm (focal length of concave mirror is always negative)
Mirror formula
1/f = 1/u + 1/v
-1/15 = -1/20 + 1/v
1/v = -1/20 + 1/15
1/v = 15-20/15×20
1/v = -5/15×20
1/v = -1/60
v = -60 cm
Focal length (f) = -15 cm (focal length of concave mirror is always negative)
Mirror formula
1/f = 1/u + 1/v
-1/15 = -1/20 + 1/v
1/v = -1/20 + 1/15
1/v = 15-20/15×20
1/v = -5/15×20
1/v = -1/60
v = -60 cm
vino101:
which answer I should write
Answered by
1
The distance of object (u) = - 20 cm
The focal length of the convex mirror (f) = 15 cm
The distance of image (v) = ?
We know that
1/v - 1/u = 1/f
1/v = 1/f + 1/u
1/v = 1/15 + 1/- 20
1/v = (4 - 3)/60
1/v = 1/60
v = 60 cm
v = 60 cm
The distance of the image = 60 cm
Hope this helps you.
The focal length of the convex mirror (f) = 15 cm
The distance of image (v) = ?
We know that
1/v - 1/u = 1/f
1/v = 1/f + 1/u
1/v = 1/15 + 1/- 20
1/v = (4 - 3)/60
1/v = 1/60
v = 60 cm
v = 60 cm
The distance of the image = 60 cm
Hope this helps you.
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