Question

what will be the power consumed by a 50 ohom wire if it is kept across a potential difference of 200 v?​

Answer 1

A wire is generally assumed to have no resistance. But if you mean a device or resistor of 25 ohms then the answer is 2500 watts. The circuit has 10 amps flowing thru it at every point and the resistance part is therefore consuming 10 times 25 = 2500 watts. If this goes on for one hour, 2500 watt/hours will be consumed. If the power company rates are 15 cents/kw, it will cost you 37.5 cents.

Answer 2

The power consumed by a 50-ohm wire if it is kept across a potential difference of 200 V is equal to 800 watts.

Given:

Resistance of wire (R) = 50 Ω

The potential difference across the wire (V) = 200 V

To Find:

The Power (P) consumed by the wire.

Solution:

→ According to Ohm's law the potential difference (V) across a wire is directly proportional to the current (I) flowing through the wire.

                           Voltage (V) ∝ Current (I)

                                           V ∝ I

                                           V = (I) × (R)

                          → where 'R' is the resistance of the wire.

∴ The current (I) flowing through the wire:

                            $Current(I)=\frac{Voltage(V)}{Resistance(R)}$

                                         $\therefore I=\frac{V}{R}= \frac{200}{50}=4A$

→ Hence the current (I) flowing through the wire is equal to 4 A.

→ The Power (P) consumed by the wire is given by:

                           $Power(P)=(V)(I)=I^{2} R=\frac{V^{2} }{R}$

→ Hence we can find the Power consumed (P) by calculating the product of Potential difference (V) and Current (I) through the wire:

                                     ∴ P = (V) × (I)

                                         P = (200) × (4)

                                         P = 800 W

Therefore the power consumed by a 50-ohm wire if it is kept across a potential difference of 200 V is equal to 800 Watts.

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