Question

what will be the power consumption of two 300 W bulbs,three 100 W fans and one 1200 W refrigerator for continuous operation of 30 hours ?​

Answer 1

To Find:

• Power consumption.

Power two bulbs = 2 × 300 = 600 W

Power of three fans = 3 × 100 = 300 W

Power of one refrigerator = 1200 W

• Total time = 30 hours

We know that:

↣ Power consumption = Total power × Total time

Finding the power consumption:

↠ Power consumption = (600 + 300 + 1200) × 30

↠ Power consumption = 2100 × 30

↠ Power consumption = 63000

∴ Power consumption = 63000 Watt-hour

Converting power consumption in kWh:

• 1000 Wh = 1 kWh
• 63000 Wh = 63000/1000 kWh
• 63000 Wh = 63 kWh

Hence,

• The power consumption will be 63 kWh.

Answer 2

Answer :-

⇒ The power consumption is 63 kWh.

Step-by-step explanation :-

Given :

⇒ Two 300 W bulbs.

⇒ Three 100 W fans.

⇒ One 1200 W refrigerator.

⇒ Time = 30 hours

To find :

⇒ Power consumption.

Solution :

Bulbs :-

⇒ 2 × 300 W

⇒ 600 W

Fans :-

⇒ 3 × 100 W

⇒ 300 W

Refrigerator :-

⇒ 1 × 1200 W

⇒ 1200 W

All appliances power :-

⇒ (600 + 300 + 1200)W

⇒ 2100 W

Power consumption :-

⇒ All appliance power × Time

⇒ 2100 × 30

⇒ 63000 Wh

⇒ 63000/1000 kWh

⇒ 63 kWh

• Power consumption is 63 kWh.