Question

what will be the power consumption of two 300 W bulbs,three 100 W fans and one 1200 W refrigerator for continuous operation of 30 hours ?​

Answer 1

Answer:

• Power consumption is 63 kWh.

Step-by-step explanation:

Given that,

• Two bulbs = 300 W

So, Power of two bulbs = 600 W

• Three fans = 100 W

So, Power of three fans = 300 W

• One refrigerator = 1200 W

• Total time = 30 hours.

Formula to be used :

Power/energy consumption = Total power/energy of appliances × Total time period.

So,

Total power = Sum of power of all appliances

= 600 W + 300 W + 1200 W

= 2100 W

Total power is 2100 W.

Power consumption = 2100 W × 30 h

Power consumption = 63000 Wh

Conversation :

1 kWh = 1000 Wh

63000 Wh = 63000/1000 kWh

= 63 kWh

∴ Power consumption in 30 hours is 63 kWh.

Answer 2

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HERE IS UR ANSWER

_____________________

Given

two bulbs=300W

power of two bulbs = 600 W

three fans=100W

power of 3 fans=300W

one refrigerator=1200 W

total time= 30 hours

Solution

energy = power × time

$power = \frac{energy}{time}$

total power= sum of all powers

= (600+300+1200)W=2100W

power consumption=1200W × 30 hrs

=63000 Wh

we know 1kWh=1000Wh

so,power consumed in 30 hrs=63kWh