what will be the power of compound lens made by combing convex and concave lens of equal power?
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Since the lens addition formula adds the reciprocal of the component focal lengths , the resulting focal length will be 1/2 the original focal length.
Here’s the break down: 1/f = 1/f1 + 1/f2. where f1 = f2.
1/f = 1/f1 + 1/f1 = 2/f1, so f = f1/2.
Similarly, if three lenses were placed in contact, then the combined focal length would be 1/3 of a single lens.
princechaudhary01:
thanks
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