Question

What will be the pressure exerted by a mixture of 3.2 gram of methane and 4.4 gram of seo2?

Answer 1

Explanation:

Here is your answer,

Moles of CH₄,

nCH₄= Mass of CH₄/Molar mass of CH₄  [ Molar mass of CH₄] = 12+4×1= 16

3.2/16 = 0.2 mol

Moles of CO₂

nCO₂ = 4.4/44 = 0.1 mol [ Molar mass of CO₂ = 12+2 ×16=44]

Total moles = 0.2 + 0.1 = 0.3 mol

pV=nRT 

Pressure, P=nRT/V

0.3 mol × 0.0821 dm³ atm K power -1 mol power -1 × 300 K/ 9 dm³ = 0.0821 atm

In terms of SI unit 

Pressure,p = 0.3 mol × 8.314 Pa m³ K power -1 mol power -1 × 300/ 9×10⁻³ m³ 

Therefore, p= 8.314×10 power 4 Pa.