What will be the pressure exerted by the of 3.2 gram of methane and 4.4 gram of carbon dioxide contained in?
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Moles of CH4,
cCH4= Mass if CH4/Molar mass of
CH4( Molar mass of CH4) =12+4+1=16
3.2/16=0.2 mol
Moles of CO2
nCO2=4.4/44=0.1mol( Molar mass of CO2 =12+2+16=0.3mol
pV=nRT
Pressure,p=nRT/V
0.3mol in to 0.0821dm3 at K power - 1
molpower - 1 300 K/ 9dm3 =0.0821 atm
pressure, p=0.3 Moles in to 8.314 a m3 K
power - 1 Moles power - 1 into 300/9in to 10-3 m3
Therefore, p=8.314 in to power 4Pa.
Answered by
0
Explanation:
8.314 =p
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