Question

What will be the pressure in dyne/ore, due to a water column of height 10 cm?
[ take g = 980 cm/5*

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Answer 1

Answer:

Pressure at the bottom of the water collumn is

P=Po+\rho gh={ 10 }^{ 6 }+1\times 980\times 12.5

P=Po+ρgh=10  

6

+1×980×12.5

                             

= 1012250  \ dyne  \ { cm }^{ -2 }

=1012250  dyne  cm  

−2

HOPE THIS WILL HELP U PLZ MARK AS BRAINLIEST

Answer 2

Answer:

Great just joking about this just as important information.