What will be the pressure of 2 moles of ideal gas at 546 K?If the volume of container in which gas is present is 50L. Please give the complete solution.
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Answered by
8
Heya user !!
Here's the answer you are looking for
The ideal gas equation says, PV = nRT
where P is the pressure
V is the volume
n is the number of moles
R is a gas constant
T is the temperature.
According to the question,
n = 2
T = 546K
V = 50l
and R = 1/12 or 0.083
Put all the values in the equation,
P (50) = (2)(0.083)(546)
P(50) = 90.636
P = 90.636 / 50 = 1.81272atm
Therefore, the pressure is 1.81272atm.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
The ideal gas equation says, PV = nRT
where P is the pressure
V is the volume
n is the number of moles
R is a gas constant
T is the temperature.
According to the question,
n = 2
T = 546K
V = 50l
and R = 1/12 or 0.083
Put all the values in the equation,
P (50) = (2)(0.083)(546)
P(50) = 90.636
P = 90.636 / 50 = 1.81272atm
Therefore, the pressure is 1.81272atm.
★★ HOPE THAT HELPS ☺️ ★★
Anonymous:
perfect
well done
we perhaps round off the decimal digits to 2 decimal places or 3... usually
yes ;)
Answered by
3
We assume that the given gas is an Ideal Gas. Let us apply the Ideal Gas Law.
Given n =2 , V = 50 L = 0.050 m³, R = 8.314 J/°K/mol , T = 546°K
P = n R T / V
P = 2 * 8.314 * 546 / 0.050
= 1.815 * 10⁵ Pa
= 1.81 atm
Given n =2 , V = 50 L = 0.050 m³, R = 8.314 J/°K/mol , T = 546°K
P = n R T / V
P = 2 * 8.314 * 546 / 0.050
= 1.815 * 10⁵ Pa
= 1.81 atm
#CONTENT QUALITY SIR!!
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