Question

What will be the pressure of a gas mixture when 1 lt of H2 gas at 0.8 bar and 1 lt of oxygen at 0.7 bar are introduced in 2 lt vessel ?

Answer 1

$\blue{\underline{ \huge{ \blue{\boxed{ \mathfrak{\fcolorbox{red}{orange}{\purple{Answer}}}}}}}}$

• Given :

=> Volume of H2 gas (V1) = 1L

=> Pressure of H2 gas (P1) = 0.8bar

=> Volume of O2 gas (V2) = 1L

=> Pressure of O2 gas (P2) = 0.7bar

=> Total volume after mixed both (V) = 2L

• To Find :

=> Total pressure after mixed both (P) = ?

• Formula :

=> As per Bauyle's law relation between pressure of gas and volume is given by...

$\underline{ \boxed{ \bold{ \rm{ \pink{P\propto{ \frac{1}{V} \: \blue{\longrightarrow} \: \: \therefore \: PV = constant }}}}}}$

=> So, we can say that...

$\: \: \: \: \underline{ \boxed{ \bold{ \rm{ \red{P_1V_1 + P_2V_2 = (PV){ \tiny{mixture}}}}}}}$

• Calculation :

$\leadsto \rm \: (1 \times 0.8) + (1 \times 0.7) = P \times 2 \\ \\ \leadsto \rm \: P = \frac{0.8 + 0.7}{2} = \frac{1.5}{2} \\ \\ \underline{ \boxed{ \bold{ \sf{ \orange{ \therefore \: P{ \tiny{mix}} = 0.75 \: bar}}}}}$