Question

what will be the pressure of the gas admixture with 0.5 litre of H2 at 0.8 and 2.0 of dioxygen at 0.7 bar are introduced in 1 litre vessel at 27 °C. ​

Answer 1

AnSwer :-

Let the partial pressure of H$_2$ in the vessel be p$\sf _{H_2}$

Now,

According to Question

• initial pressure, p$_1$ = 0.8bar
• final pressure, p$_2$ = p$\sf _{H_{2}}$
• initial Velocity, v$_1$ = 0.5L
• final velocity, v$_2$ = 1L

It is known that,

• p$_1$V$_1$ = p$_2$V$_2$

➠ p$_2$ = p$_1$V$_1$ /v$_2$

➠ p$\sf _{H_2}$ = 0.8 × 0.5/1

➠ p$\sf _{H_2}$ = 0.4bar

Now, let the partial pressure of O$_2$ in the vessel be p$\sf _{O_2}$

According to Question,

• initial pressure, p$_1$ = 0.7 bar
• final pressure, p$_2$ = p$\sf _{O_2}$
• initial velocity, V$_1$ = 2.0 L
• final velocity, V$_2$ = 1L

we know that,

• p$_1$V$_1$ = p$_2$V$_2$

➠ p$_2$ = p$_1$V$_1$ /v$_2$

➠ p$\sf _{O_2}$ = 0.7 × 20 /1

➠ p$\sf _{O_2}$ = 1.4bar

Total pressure of the gas mixture in the vessel can be obtained as :-

p$\sf _{total}$ = p$\sf _{H_2}$ + p$\sf _{O_2}$

= 0.4 + 1.4

= 1.8 bar

Hence, the total pressure of the gaseous mixture in the vessel is 1.8bar.