Question

What will be the pressure of the gaseous mixture when 0.5 L of “Ne” at 0.8 bar and 2L of O2 at

0.7 bar introduced in a 1L vessel at 270C ?​

Answer 1

Answer:

Explanation:

(i) The partial pressure of hydrogen gas  

P  

′

=  

V  

′

 

PV

​  

=  

1

0.8×0.5

​  

=0.40 bar

(ii) The partial pressure of oxygen gas  

P  

′′

=  

V  

′

 

PV

​  

=  

1

0.7×2.0

​  

=1.40 bar

So, the total pressure of gaseous mixture is P+P  

′′

=0.40+1.40=1.80 bar