Question

What will be the pressure required to reduce 500 cm3 of a dry gas at 750 mm pressure to150 cm 3 at the same temperature.​

Answer 1

Answer:

1

p

V

1

=P

2

V

2

⇒600×750=500×P

2

∴P

2

=900mmHg

∴ Increase in pressure= P

2

−P

1

=(900−750)=150mm

Explanation:

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