Question

what will be the probebily of losing a game if the winning probebility is 0.3?

Answer 1

Answer:

it is 0.7

Step-by-step explanation:

p(E)=n(E)+n(Enot)

p(E)=1

n(e)=0.3

1-0.3=n(Enot)

n(Enot)=0.7

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