Question

What will be the radius of base if a cone whose height is 6m and slant height is 10 m

Answer 1

Answer:

Given :-

• A cone whose height is 6 m and slant height is 10 m.

To Find :-

• What is the radius of a base.

Formula Used :-

$\clubsuit$ Pythagoras Theorem Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{(l)^2 =\: (r)^2 + (h)^2}}}\: \: \: \bigstar$

where,

• l = Slant Height
• r = Radius
• h = Height

Solution :-

Given :

• Height = 6 m
• Slant Height = 10 m

According to the question by using the formula we get,

$\implies \bf (l)^2 =\: (r)^2 + (h)^2$

$\implies \sf (10)^2 =\: (r)^2 + (6)^2$

$\implies \sf (10 \times 10) =\: (r)^2 + (6 \times 6)$

$\implies \sf 100 =\: r^2 + 36$

$\implies \sf 100 - 36 =\: r^2$

$\implies \sf 64 =\: r^2$

$\implies \sf \sqrt{64} =\: r$

$\implies \sf \sqrt{\underline{8 \times 8}} =\: r$

$\implies \sf 8 =\: r$

$\implies \sf\bold{\red{r =\: 8\: m}}$

$\therefore$ The radius of a base of cone is 8 m .