what will be the range of the temperature of the mixture upon mixing water at 40°C With water at 60 °C ?
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Answered by
3
Answer:
50°C
Explanation:
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Answered by
3
Answer:
Change in energy: Q = m*c*DT
m is mass
c is specific heat
DT is change in temperature
Energy Lost = (200 g)*c*(60 - T_final)
Energy Gained = (500 g)*c*(T_final - 40)
Energy Lost = Energy Gained
200*(60 - T_final) = 500*(T_final - 40)
12000 - 200*T_final = 500*T_final -20000
32000 = 700*T_final
T_final = 320/7 = 45.7 C
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