Question

what will be the range of the temperature of the mixture upon mixing water at 40°C With water at 60 °C ?​

Answer 1

Answer:

50°C

Explanation:

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Answer 2

Answer:

Change in energy: Q = m*c*DT

m is mass

c is specific heat

DT is change in temperature

Energy Lost = (200 g)*c*(60 - T_final)

Energy Gained = (500 g)*c*(T_final - 40)

Energy Lost = Energy Gained

200*(60 - T_final) = 500*(T_final - 40)

12000 - 200*T_final = 500*T_final -20000

32000 = 700*T_final

T_final = 320/7 = 45.7 C