what will be the ratio of area of two parallelogram which lies on same base and between same parallels?
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Answer:
area of first parallelogram is A = B*H
area of second parallelogram a = b * h
for same base area and parallel lines B=b , and H = h
so ratio of two area = A/a
= B* H/ b *h
= b *h / b*h
= 1:1
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