Physics, asked by arunkshma4351, 11 months ago

What will be the ratio of de - Broglie wavelengths of proton and alpha - particle of same energy ?

Answers

Answered by ayushkishormkv

Answer:

Kinetic energy K = p^2/2m where m is the mass and p is the momentum. Thus, p = sqrt(2mK) = square root from 2mK. Wavelength = h/p = h/sqrt(2mK), where h is Planck's constant. The De Broglie wavelength of a particle is , thus the ratio .

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