what will be the ratio of time taken to free fall by 2 bodies of masses m1 and m2 from height h1 and h2
Answers
Answered by
0
Answer:
v = u + a*t
Initial Velocity u
m/s
Final Velocity v
m/s
Time t
s
Acceleration a
m/s²
RESET VALUES
ANSWER
From second equation of motion,
s=ut+
2
1
at
2
Given, u=0, a=g, s
1
=h
1
, s
2
=h
2
h
1
=(1/2)g(t
1
)
2
h
2
=(1/2)g(t
2
)
2
So, h
1
/h
2
=(t
1
)
2
/(t
2
)
2
or(t
1
)/(t
2
)=
h
2
h
1
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