what will be the ratio of volumes of equal masses of O2, H2, CH4 kept in the same container under same condition?
A. 2:16:2
B. 1:16:2
C. 2:16:1
D. 1:2:1
plz answer must and immediately
PLEASE PLEASE.....
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Answers
Answered by
1
Hey,
We take v ml of each gases..H2,o2,CH4
H2=V/2, 02=V/32,CH4=V/16
Now limiting one is V/32
V/2/V/32=16 for H2
V/32/V/32=1 for O2
V/16/V/32=2 for CH4
Now the ratio is 1:16:2 i.e., B
HOPE IT HELPS:-))
We take v ml of each gases..H2,o2,CH4
H2=V/2, 02=V/32,CH4=V/16
Now limiting one is V/32
V/2/V/32=16 for H2
V/32/V/32=1 for O2
V/16/V/32=2 for CH4
Now the ratio is 1:16:2 i.e., B
HOPE IT HELPS:-))
pgcpattoki27072001:
limiting one means?
Answered by
2
b is the option for your question
as.
O2 : H2 : CH4
2(16) : (2) : ( 12+4)
32 : 2 : 16
toequal masses
(32) : 16 (2) : 2 (16) pp
so ratio is 1:16:2
hope it helps you a lot.....!!!!!
as.
O2 : H2 : CH4
2(16) : (2) : ( 12+4)
32 : 2 : 16
toequal masses
(32) : 16 (2) : 2 (16) pp
so ratio is 1:16:2
hope it helps you a lot.....!!!!!
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