what will be the ratios of sides for sec A and cosA
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Given:- The figure with A as perpendicular and B as base.
To find:- what will be the ratios of sides for sec A and cosA
SOLUTION:-
• Now we have given the figure .
• Perpendicular is A and base is B.
• So hypotenuse will be---
C = √( a² + b² )
•Now:
Sec A = Hypotenuse/Base
Sec A = C = √( a² + b² ) /b
Cot A = Base / Perpendicular
Cot A = b/a
Answer:-
So, sec A is √( a² + b² ) /b and cot A is b/a
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