what will be the remainder when 5x^2-x^2+6x-2 is divided by 1-5x
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Answer:
5x²-x²+6x-2
divide with 1-5x
1-5x=0
-5x=-1
X=1\5
5(1\5)²-(1\5)²+6(1\2)-2=0
(5\5)-(1\5)+(6\5)-2=0
1-(1\5)+(6\5)-2=0
1-(7\5)-2=0
(-7\5)-2= -1
(7\5)-2=1
(7\5)=3
X=(21\5)
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