Question

What will be the remainder when 6x^5 + 4x^4 - 27x^3-7x^2 + 27 X +3/2 is divided by (2x^2-3)?​​​

Answer 1

Answer:

remainder will be 0

Step-by-step explanation:

6x^5 + 4x^4 - 27x^3 - 7x^2 + 27x + 3/2

multiplying all by 2 ,

12x^5 + 8x^4 - 54x^3 - 14x^2 + 54x + 3 -----------1

2x^2 - 3 -------------2

dividing 1 by 2 ,

we get the ans which is in the img above