Question

what Will be the remainder when 6x^5+4x^4-27x^3-7x^2+27x+3/2 is divided by (2x^2-3)?​

Answer 1

Answer:

 

The remainder is $-x^{2}$ +$\frac{3}{2}$.

The procedure is attached down.

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Answer 2

Answer:

The answer (remainder) is

$- {x}^{2} + \frac{3}{2}$