Question

What will be the remainder when 6x5+4x4-27x3-7x2+27x+3/2 is divided by (2x2-3)? ​

Answer 1

Answer:

Step-by-step explanation:

2x^2-3÷6x^5+4x^4-27x^3-7x^2-27x-6

1st Step:-6x^5+4x^4-27x^3-7x^2-27x-6

              6x^5          -9x^3

2nd step:-         4x^4-18x^3-7x^2-27x-6

                         4x^4          -6x^2

3rd step:-                  -18x^3-x^2-27x-6

                                -18x^3        +27x

4th step:-                             -x^2- 54x-6

                                           -x^2         +3/2

5th step:-                                     -54x-15/2

Thus -54x-15/2 is to be added with 6x^5+4x^4-27x^3-7x^2-27x-6 if it is exactly divisible by 2x^2-3