Question

what will be the remainder when a x power 6 minus 3 x square minus 10 is divided by x cube - 1 ​

Answer 1

Heyy Mate here is Ur Answer....

Let the polynomial be =

p(x) = x³-ax²+6x-a

Then g(x) = x-a

To Find : It's remainder when p(x) is divided by g(x) .

Solution :

Consider g(x) = 0

x-a=0

x = a

Put x = a in p(x)

p(x) = x³-ax²+6x-a

= a³-a×a²+6a-a

= 5a

The required remainder = 5a

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