Question

What will be the remainder when the sum of all the 5-digit numbers that can be formed using the digits 1 and 2, is divided by 10?​

Answer 1

Answer:

k = 28

Step-by-step explanation:

First compare the divisor with (x-h)  

Here, our divisor is 2x+1, lets make it in the form of x-a by taking 2 common first as theres a coefficient infront of x.

(2x+1) = 2(x+1/2) = 2[x-(-1/2)]

comparing this with (x-h), we get h = -1/2

Now using the remainder theorem,

4x³-2x²+kx+5= -10

Replace x with h = -1/2

4(-1/2)³-2(-1/2)²+k(-1/2) +5 = -10

Now solve for k and you will get k = 28.

Answer 2

the remainder when the sum of all the 5-digit numbers that can be formed using the digits 1 and 2, is divided by 10

First compare the divisor with (x-h)  

Here, our divisor is 2x+1, lets make it in the form of x-a by taking 2 common first as theres a coefficient infront of x.

(2x+1) = 2(x+1/2) = 2[x-(-1/2)]

comparing this with (x-h), we get h = -1/2

Now using the remainder theorem,

4x³-2x²+kx+5= -10

Replace x with h = -1/2

4(-1/2)³-2(-1/2)²+k(-1/2) +5 = -10

Now solve for k and you will get k = 28.