Question

what will be the remainder when x6-3x^2-10 is divided by x3-1

Answer 1

hope this will help you

Answer 2

$Let \: p(x) = x^{6} - 3x^{2} - 10 \: and \\g(x) = x^{3} - 1$

x³-1| x⁶+ 0 - 3x^{2} - 10 | x³ + 1

***** x⁶ - x³

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********* x³ - 3x² - 10

********* x³+ 0 - 1

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Remainder = -3x² - 9

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• Dividend = x⁶ - 3x² - 10
• Divisor = x³ - 1
• Quotient = x³ + 1
• Remainder = - 3x² - 9 ,

Therefore.,

$\red{ Remainder }\green {= (-3x^{2} - 9 ) }$

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