Question

What will be the resistance of a metal wire length 2m and radius 2× 10 -3 and resistivity 2.8 ×10 -8 ohm meter

Answer 1

Explanation:

therefore

$r \: = \: 0.44 \times 10^{</strong><strong>-</strong><strong>2}$

Answer 2

Answer:

4459 micro ohm

Explanation:

given

length of the wire = 2m

radius of cross section= 2×10^(-3) m

resistivity of metal of wire = 2.8×10^(-8) ohm meter

resistance (R)

= resistivity× length / area of cross section

= (2.8×10^(-8) × 2) / (3.14×4×10^(-6) )

= 0.4459×10^(-2)

= 4459×10(-6) ohm

= 4459 micro ohm

therefore resistance of the wire

= 4459 micro ohm