What will be the result stored in x after evaluating the following expression ? int x=4; x+=(x++)+(++x)+x;
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Explanation:
x+=(x++)+(++x)+x; // (x+=) is a short hand operator which means x=x+ and (x++) is a post fix operator which will use the old value of x first and then change the value internally and at the next time the variable will be used it will use the new value
x=4+4+6+6;
x=20;
hope it helps if not then sorryyyyyyyyy
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