Question

What will be the result when each term sin^(2)theta+cos^(2)theta=1 is divided by sin^(2)theta ?​

Answer 1

Answer:

Let a, b, c be lengths of right angled triangle

By definition

sinθ=b/c(

hypotenuse

opposite side

)

cosθ=a/c(

hypotenuse

adjacent side

)

sin

2

θ+cos

2

θ=

c

2

b

2

+

c

2

a

2

=

c

2

a

2

+b

2

From Pythagoras theorem

c

2

=a

2

+b

2

∴

c

2

a

2

+b

2

=1

sin

2

θ+cos

2

θ=1

Hence, proved.

Answer 2

Answer:

Step-by-step explanation:

we know that sin^2 Ф+cos^2theta=1--------1

now

sin^2theta+cos^2theta/sin^2theta

from 1

1/sin^2theta

we know that    1/sin theta=cosec theta -----------2

1/sin^2theta=cosec^2theta  (from 2)

hence the value is cosec^2 theta

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