What will be the resultant ph when 200ml of an aqueous solution of hcl(ph=2.0)is mixed with 300 ml of solution of naoh (ph=13)?
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From 200ml hcl
[H+]=200ml × 10^(-2)=2M
From 300ml naoh
[H+]=300ml × 10^(-13)=3 × 10^(-11)M
total H+ = 2M + 3× 10^(-11)M=2M
total volume=200+300=500ml
average H+=2/500=4× 10^(-3)
now taking negative logarithm that is
pH=2.398
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