Question

what will be the resultant velocity? ​

Answer 1

Velocity 1 = 30m/s east

Velocity 2 = 40m/s north

Then, ∅ will be equal to 90° cause north and east direction are perpendicular to each other.

Resultant velocity =

$\sqrt{30 {}^{2} + 40 {}^{2} + 2 \times 30 \times 40 \times cos90 }$

$\sqrt{900 + 1600 + 2400cos90}$

since cos90° = 0

$\sqrt{900 + 1600}$

$\sqrt{2500}$

$50$

Magnitude of resultant velocity = 50m/s

tanß = bsin∅/a+bcos∅

tanß = 40sin90/30+40cos90

tanß = 40/30

{because sin90° = 1 and cos90° = 0}

tanß = 4/3

ß= tan-¹(4/3) in North of east

Cheers!

Answer 2

What do you mean by osmosis