What will be the resulting normality of NaCl solution formed on mixing 200ml of decimolar NaOH with 40ml of semimolar HCl?
Magnetron:
normality will be equal to molarity here, so use molarity of mixing formula
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The equation is,
NaOH + HCl --------------> NaCl + H2O
Initially, 200 x 0.1 40 x 0.5
20moles 20moles 0 0
after
some time 0 0 20 20
Since both the acid and the base are present in equal amounts, complete neutralisation takes place.
Now the total volume is 200 + 40 = 240ml
Molarity of NaCl formed = moles/volume(in litres)
= 1000/12 =83.33
As the n-factor is 1 in this case molarity is equal to normality.
Therefore, Resultant Normality = 83.33
NaOH + HCl --------------> NaCl + H2O
Initially, 200 x 0.1 40 x 0.5
20moles 20moles 0 0
after
some time 0 0 20 20
Since both the acid and the base are present in equal amounts, complete neutralisation takes place.
Now the total volume is 200 + 40 = 240ml
Molarity of NaCl formed = moles/volume(in litres)
= 1000/12 =83.33
As the n-factor is 1 in this case molarity is equal to normality.
Therefore, Resultant Normality = 83.33
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