Question

What will be the SI on rupees 1200 at the rate of 2 P per rupee per month for 2 months?

Answer 1

Given:-

•Principal on 1200 rupees at the rate of 2 P per rupee per month and time is given 2 months.

To Find:-

•We are said to find Simple Interest.

Solution:-

Given,

• Principal = 1200 rupees
• Time = 2 months = $\dfrac{2}{12}$ = $\dfrac{1}{6}$ years

We know that,

$\: \: \sf \: rate = \frac{simple \: interest \times 100}{principal \times time}$

Now substitute the values,

$\: \: \sf \: rate = \frac{2 \times 100 \times 12 }{100} \\ \\ \: \: \sf \: rate = 24 \: percent$

Now,

• Rate= 24%
• Time = $\dfrac{1}{6}$ years
• Principal = 1200 rupees

As we know,

$\: \: \sf \: simple \: interest = \frac{principal \times time \times rate}{100}$

Now substitute the values,

$\: \: \sf \: simple \: interest = \frac{1200 \times 1 \times 24}{6 \times 100} \\ \\ \: \: \sf \: simple \: interest = 48 \: rupees$

$\therefore$

Hence,Simple interest is 48 rupees.

Answer 2

Rs.1264 should be repaid after 8 months .

Step-by-step explanation:

• Principal = Rs.1200

❏ Time = 8 months =$\sf\frac{2}{12} years$

❏ Rate of interest = 24%

Simple interest = $\sf\frac{P \times T \times R}{100}$

Now substitute the values,

$\begin{gathered} \: \: \sf \: ⇝ Simple \: interest = \frac{1200 \times 1 \times 24}{6 \times 100} \\ \\ \: \: \sf \: ⇝ Simple \: interest = 48 \:rupees\end{gathered}$

❏ Simple interest =48

• Rate= 24%
• Time = $\dfrac{1}{6}$years
• Principal = 1200 rupees

$\sf ❏ \:Hence\: Rs.48\: should \:be\: repaid \:after\: 2\: months$