Question

What will be the signs of potential difference VP – VQ, VA - VB from the

diagram given ?

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Answer 1

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$\bold{Explanation:}$

i) when q >0

Potential difference between two points in an electrostatic field is the amount of work in moving a unit +ve charge from one point to another against the field .

Here VA>VB

∴VA−VB is positive

(ii) if q <0

Here we move unit +ve charge from A in order to go against the field.

VB>VA

∴VA−VB is negative

Answer 2

Explanation:

POTENTIAL DECREASES IN THE DIRECTION OF FIELD (as E= -dv/dr) so Vq<Vp so Vp-Vq is +ve.

Now, similarly Va<Vb so Vb-Va is also +ve