What will be the simple interest on ₹ 12,000 for 2 years at 10 p.c.p.a... *
Answers
Answered by
3
Answer
Here P=12,000 Rs., n=2 years, R=10
Amount(A)=P(1+
100
R
)
n
=12000(1+ 100÷10
)
2
=12000( 10+11
=
100
12000×121 =14,520 Rs.
Compound interest(C.I)=A−P=14,520−12,000=2520
Hence, the compound interest is Rs. 2,520
Answered by
2
Answer:
Answer is Rs.2400
Step-by-step explanation:
Principal - Rs. 12000
Rate of Interest- 10 p.c.p.a.
Time - 2years
S.I - P X R X T / 100
12000 X 10 X 2 / 100
ANS - 2400
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