what will be the solution of this question
"(n+1) term in Mactaurin's series of tan x
is'
Answers
Answered by
1
Answer:
The answer is
=
x
+
x
3
3
+
o
(
x
3
)
Explanation:
Let
f
(
x
)
=
tan
x
,then
f
(
0
)
=
0
f
'
(
x
)
=
sec
2
x
=
1
+
tan
2
x
,
⇒
,
f
'
(
0
)
=
1
f
'
'
(
x
)
=
2
sec
x
(
1
+
tan
2
x
)
,
⇒
,
f
'
'
(
0
)
=
2
The Maclaurin series expansion is
tan
x
=
f
(
0
)
+
x
f
'
(
0
)
+
x
2
2
!
f
'
'
(
x
)
+
x
3
3
!
f
'
'
'
(
x
)
+
...
=
x
+
x
3
3
+
o
(
x
3
)
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